General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 13 - Rates of Reaction - Exercises - Page 538: 13.2

Answer

$\frac{-1\Delta{HBr}}{4\ \Delta t}$

Work Step by Step

$\frac{-1\Delta{HBr}}{4\ \Delta t}$ = $\frac{1\Delta{Br}}{2\ \Delta t}$
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