General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 12 - Solutions - Questions and Problems - Page 532: 12.138


Please see the work below.

Work Step by Step

We know that $Molarity=\frac{moles of solute}{Liters of solution}$ We plug in the known values to obtain: $Molarity=\frac{0.08058mol}{0.08517L}=0.9461\frac{mol}{L}$
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