Answer
Please see the work below.
Work Step by Step
We know that
$S_2=\frac{P_2S_1}{P_1}$
We plug in the known values to obtain:
$S_2=\frac{3.74099atm(\frac{0.00175g}{100ml})}{1.00atm}=\frac{0.006546g}{100ml}$
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