Chapter 22 - Chemistry of the Nonmetals - Exercises - Page 994: 22.72c

$NaBH_{4}$, Oxidation state of Boron is +3

Work Step by Step

Net oxidation state of the compound is 0, hence: Na: +1 x 1 = +1, H: -1 x 4 = -4 (when Hydrogen is in the form of Hydride, it has oxidation state of -1), hence B should have oxidation state of +3.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.