Answer
$NaBH_{4}$, Oxidation state of Boron is +3
Work Step by Step
Net oxidation state of the compound is 0, hence:
Na: +1 x 1 = +1, H: -1 x 4 = -4 (when Hydrogen is in the form of Hydride, it has oxidation state of -1), hence B should have oxidation state of +3.