Answer
$Na_{2}B_{4}O_{7}.10H_{2}O$, Oxidation state of B is +3
Work Step by Step
Net oxidation state of the compound is 0, hence:
Na: +1 x 2 = +2, O: -2 x 7 = -14, hence B should have oxidation state of +3 (+3 x 4= +12).
Chemistry: The Central Science (13th Edition)
by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.
Published by
Prentice Hall
ISBN 10:
0321910419
ISBN 13:
978-0-32191-041-7
Chapter 22 - Chemistry of the Nonmetals - Exercises - Page 993: 22.71d
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