Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 8 - Properties of Gases - Questions for Review and Thought - Topical Questions - Page 370c: 71a


93 atm

Work Step by Step

$V=2.00\,L$ $n= 7.0\,mol$ $T=(50+273)K=323\,K$ $R=0.0821\,L\,atm\,mol^{-1}K^{-1}$ $PV=nRT$ (ideal gas law) $\implies P=\frac{nRT}{V}=\frac{(7.0\,mol)(0.0821\,L\,atm\,mol^{-1}K^{-1})(323\,K)}{2.00\,L}$ $=93\,atm$
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