Answer
93 atm
Work Step by Step
$V=2.00\,L$
$n= 7.0\,mol$
$T=(50+273)K=323\,K$
$R=0.0821\,L\,atm\,mol^{-1}K^{-1}$
$PV=nRT$ (ideal gas law)
$\implies P=\frac{nRT}{V}=\frac{(7.0\,mol)(0.0821\,L\,atm\,mol^{-1}K^{-1})(323\,K)}{2.00\,L}$
$=93\,atm$
