Answer
$10.4\,L\,O_{2}$
$10.4\,L\,H_{2}O$
Work Step by Step
At the same T and P, volumes of gases are proportional to the coefficients in the balanced chemical equation. Therefore,
$V(O_{2})=5.2\,L\,SiH_{4}\times\frac{2\,L\,O_{2}}{1\,L\,SiH_{4}}=10.4\,L$
$V(H_{2}O)=5.2\,L\,SiH_{4}\times\frac{2\,L\,H_{2}O}{1\,L\,SiH_{4}}=10.4\,L$
