## Chemistry: The Molecular Science (5th Edition)

$\nu = 1.1*10^{-15} s^{-1}$ $E=7.4*10^{-19}J$
Energy is given by: $E = \frac{hc}{ \lambda}$ $E = \frac{6.625*10^{-34}*3*10^8}{ 270*10^{-9}}$ $E=7.4*10^{-19}J$ Frequency is given by: $\lambda = \frac{c}{ \nu}$ Substituting gives: $1.1*10^{-15} s^{-1}$