Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 5 - Electron Configurations and the Periodic Table - Questions for Review and Thought - Topical Questions - Page 240: 16


$E = 3.03*10^{-19}J$

Work Step by Step

We know that: $E = \frac{hc}{ \lambda}=h \nu$ $E = 6.625*10^{-34}*4.57*10^{14}$ $E = 3.03*10^{-19}J$
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