Answer
$E = 3.03*10^{-19}J$
Work Step by Step
We know that:
$E = \frac{hc}{ \lambda}=h \nu$
$E = 6.625*10^{-34}*4.57*10^{14}$
$E = 3.03*10^{-19}J$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 5 - Electron Configurations and the Periodic Table - Questions for Review and Thought - Topical Questions - Page 240: 16
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