Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 5 - Electron Configurations and the Periodic Table - Questions for Review and Thought - Topical Questions - Page 240: 15



Work Step by Step

We know that: $E = \frac{hc}{ \lambda}$ When we substitute, we find: $E = \frac{6.625*10^{-34}*3*10^8}{ 450*10^{-9}}$ $E=4.4*10^{-19}$
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