## Chemistry: The Molecular Science (5th Edition)

$E=4.4*10^{-19}$
We know that: $E = \frac{hc}{ \lambda}$ When we substitute, we find: $E = \frac{6.625*10^{-34}*3*10^8}{ 450*10^{-9}}$ $E=4.4*10^{-19}$