Answer
23.6 m/s
Work Step by Step
Kinetic energy $E_{k}= \frac{1}{2}mv^{2}$
$\implies v=\sqrt {\frac{2E_{k}}{m}}=\sqrt {\frac{2\times15.75\,J}{56.6\times10^{-3}\,kg}}$
$=23.6\,m/s$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 4 - Energy and Chemical Reactions - Questions for Review and Thought - General Questions - Page 189f: 100
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