## Chemistry: The Molecular Science (5th Edition)

$I$ is the correct letter.
1. Identify all solutions: $C, F, G$ and $I$. 2. Analyze their hydronium concentrations: $C$: $[OH^-] * [H_3O^+] = Kw = 10^{-14}$ $3 \times 10^{- 5} * [H_3O^+] = 10^{-14}$ $[H_3O^+] = \frac{10^{-14}}{ 3 \times 10^{- 5}}$ $[H_3O^+] = 3.333 \times 10^{- 10}M$ So, this is not valid. $F$: Strong base: $[OH^-] = [LiOH] = 0.1M$ $[OH^-] * [H_3O^+] = Kw = 10^{-14}$ $0.1 * [H_3O^+] = 10^{-14}$ $[H_3O^+] = \frac{10^{-14}}{0.1}$ $[H_3O^+] = 1 \times 10^{- 13}M$ So, this is not valid. $G:$ $[H_3O^+] = 2 \times 10^{-8}M$ So, this is not valid. $I:$ Strong acid: $[H_3O^+] = [HClO_4] = 0.010M$ $[H_3O^+] = 0.010M$ This is valid: $0.010M > 1.0 \times 10^{-7}M$