Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 13 - The Chemistry of Solutes and Solutions - Questions for Review and Thought - Topical Questions - Page 605b: 30



Work Step by Step

Given: $P_{O_{2}}= 100.\,mmHg$ and $k_{H}=1.5\times10^{-6} mol \,L^{-1} mmHg^{-1}$ According to Henry's law, $S_{O_{2}}=k_{H} \times P_{O_{2}}$ $=1.5\times10^{-6} mol \,L^{-1} mmHg^{-1}\times100\,mmHg=1.5\times10^{-4}mol/L$ Concentration of $O_{2}$ in g/L= $1.5\times10^{-4}mol/L\times\frac{16\,g}{1\,mol}=2.4\times10^{-3}\,g/L$
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