Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Let's Review: The Tools of Quantitative Chemistry - Study Questions - Page 43d: 49


$8.0\times10^{4} kg\ NaF$

Work Step by Step

Data provided: Population 150,000 people Water consumption 660 L/ Water density $1.0\ g/cm^3 = 1.0\ kg/L$ Fluoride concentration in water $1\times10^{-6} kg\ F^-/kg\ water$ Fluoride mass percentage in sodium fluoride $45.0\%=0.450\ kg\ F^-/kg\ NaF$ Yearly water consumption in kg $150,000\ people \times 660\ L/ \times 365\ days/year\times1.0\ kg/L=3.6\times10^{10} kg$ Yearly fluoride consumption $3.6\times10^{10} kg \times 1\times10^{-6} kg\ F^-/kg\ water = 3.6\times10^{4} kg\ F^-$ Yearly NaF consumption $3.6\times10^{4} kg \div0.450\ kg\ F^-/kg\ NaF = 8.0\times10^{4} kg\ NaF$
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