Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Let's Review: The Tools of Quantitative Chemistry - Study Questions - Page 43d: 48


$0.018\ mm$

Work Step by Step

The mass in grams is: $12\ oz. \times \frac{28.4\ g}{1\ oz.} = 340\ g$ Given the density of $2.70\ g/cm^3$, the volume is: $V=340\div2.70=130\ cm^3$ The area in cm² is: $75\ ft^2\times\left(\frac{30.48\ cm}{1\ ft}\right)^2=70\times10^3\ cm^2$ Since the volume is given by: $V=A\times t$, the thickness is: $1.8\times10^{-3}\ cm=0.018\ mm$
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