Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Let's Review: The Tools of Quantitative Chemistry - Study Questions - Page 43d: 47


a) $15.2\%$ b) $3628.8\ kernels/lb$

Work Step by Step

a) Difference in mass: $0.125\ g - 0.106\ g = 0.019\ g$ Percentage of mass that was lost: $\frac{0.019}{0.125}\times100\%=15.2\%$ b) Converting pounds to kernels: $\frac{453.6\ g}{1\ lb}\times\frac{1\ kernel}{0.125\ g}=3628.8\ kernels/lb$
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