Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Let's Review: The Tools of Quantitative Chemistry - Study Questions - Page 43d: 44


$0.0854\ cm^3$

Work Step by Step

The mass of the diamond is given by: $1.50\ carat \times \dfrac{0.200\ g}{1\ carat}=0.300\ g$ And we're given the density ($\rho=3.513\ g/cm^3$), so the volume is: $V=0.300 \div 3.513 = 0.0854\ cm^3$
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