# Let's Review: The Tools of Quantitative Chemistry - 1 Units of Measurement - Review & Check for Section 1: 6

D

#### Work Step by Step

We use stoichiometry, making sure that all units cancel out to $\mu g/L$, to find: $0.02\ \mu g/L \times 1\ g/10^6\mu g=2\times10^{-8}\ \mu g/L$

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