Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 9 Bonding and Molecular Structure: Orbital Hybridization and Molecular Orbitals - 9-3 Molecular Orbital Theory - Review & Check for Section 9-3 - Page 365: 1



Work Step by Step

Nitrogen has 7 electrons in total, oxygen has 8. Configuration: $\sigma_{1s}\ \sigma_{1s}^*\ \sigma_{2s}\ \sigma_{2s}^*\ 3×\sigma_{2p}\ 3×\sigma_{2p}^*$ There are 10 electrons in bonding orbitals and 5 in antibonding so: $B.O.=(N.\ Bonding -N.\ Antibonding)/2$ B.o. = 5/2=2.5
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