## Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning

# Chapter 7 The Structure of Atoms and Periodic Trends - 7-6 Periodic Trends and Chemical Properties - Applying Chemical Principles - Questions - Page 280: 5

#### Answer

See the answer below.

#### Work Step by Step

$c=\lambda\times\nu$ $\nu=2.998\times10^8\ m/s\div 612\times10^{-9}\ m=4.90\times10^{14}\ 1/s$ $E=h\times\nu$ $E=6.626\times10^{-34}\ J.s\times 4.90\times10^{14}\ 1/s=3.25\times10^{-19}\ J$

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