Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 5 Principles of Chemical Reactivity: Energy and Chemical Reactions - Study Questions: 55

Answer

See answer below.

Work Step by Step

a) From the standard states: $2\ Cr(s)+3/2\ O_2(g)\rightarrow Cr_2O_3(s)$ Enthalpy of formation: $-1134.7\ kJ/mol$ b) Number of moles of Cr: $2.4\ g\div 51.996\ g/mol=0.046\ mol$ Enthalpy: $0.046\ mol\times 1/2\times-1134.7\ kJ/mol= -26.2\ kJ$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.