Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - 4-8 Spectrophotometry - Applying Chemical Principles - Questions - Page 178: 4


$29.10\ mL$

Work Step by Step

Number of moles of $OH^-$: $200.\ mg\div78.00\ mg/mmol\times3+200.\ mg\div58.32\ mg/mmol\times2=14.55\ mmol$ Same number of moles of acid to complete neutralization: $14.55\ mmol\div0.500\ M=29.10\ mL$
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