## Chemistry and Chemical Reactivity (9th Edition)

a) $CaCO_3(s)+2\ HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+ CO_2(g)$ b) $20.0\ mL$
a) $CaCO_3(s)+2\ HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+ CO_2(g)$ b) Number of moles of calcium carbonate: $500.\ mg/100.09\ mg/mmol=5.00\ mmol$ Number of moles of HCl: $5.00\ mmol\times \dfrac{2\ mmol\ HCl}{1\ mmol\ CaCO_3}=10.0\ mmol\ HCl$ Volume: $10.0\ mmol\div0.500\ M=20.0\ mL$