## Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning

# Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - 4-4 Chemical Equations and Chemical Analysis - Review & Check for Section 4-4 - Page 156: 1

C

#### Work Step by Step

$CO_2$: $1.316\ g\div44.01\ g/mol=0.0299\ mol$ C: $0.0299\ mol\times12.01\ g/mol=0.359\ g$ $H_2O$: $0.269\ g\div18.01\ g/mol=0.0149\ mol$ H: $2\times0.0149\ mol\times1.008\ g/mol=0.0300\ g$ O: $(0.509-0.359-0.0300)\ g\div 16.00\ g/mol=0.00750\ mol$ Dividing by the smallest value: C: $0.0299/0.00750=4.0$ H: $2\times0.0149/0.00750=4.0$ Empirical formula: $C_4H_4O$

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