Answer
$[F^-]=1.31\times10^{-4}\ M$
Work Step by Step
$K_{sp}(CaF_2)=3.45\times10^{-11}$
$K_{sp}=[Ca^{2+}][F^-]^2$
$3.45\times10^{-11}=2.0\times10^{-3}[F^-]^2$
$[F^-]=1.31\times10^{-4}\ M$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677d: 84
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
