## Chemistry and Chemical Reactivity (9th Edition)

$K_{sp} = (3.6 \times 10^{-6})$
1. Write the $K_{sp}$ expression: $TlBr(s) \lt -- \gt 1Tl^{+}(aq) + 1Br^{-}(aq)$ $K_{sp} = [Tl^{+}]^ 1[Br^{-}]^ 1$ 2. Calculate the $K_{sp}$: $K_{sp} = (1.9 \times 10^{-3}) \times (1.9 \times 10^{-3})$ $K_{sp} = (3.6 \times 10^{-6})$