Answer
$3.46\times10^{-7}\ mol$
Work Step by Step
The molar mass of atropine is: $289.37\ g/mol$
Therefore the number of moles of 100 mg is:
$(100/1000)g \div 289.37\ g/mol=3.46\times10^{-7}\ mol$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - 16-7 Calculations with Equilibrium Constants - Case Study - Questions - Page 614: 1
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