Answer
A
Work Step by Step
$pH=-log10([H_3O^+])$
$[H_3O^+]=10^{-4.32}=4.79\times10^{-5}\ M$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - 16-2 Water and the pH Scale - Review & Check for Section 16-2 - Page 592: 2
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