Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583f: 58


$n_{CaCO_3}=0.1854\ mol$

Work Step by Step

$K_p=p(CO_2)$ $p(CO_2)=3.87\ atm$ $n_{CO_2}=n_{CaCO_3}=p(CO_2)V/RT$ $n_{CaCO_3}=3.87\ atm\times 5.00\ L/(0.082\ L.atm/mol.K\times1273\ K)$ $n_{CaCO_3}=0.1854\ mol$
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