## Chemistry and Chemical Reactivity (9th Edition)

a) The equilibrium will shift to the right, $[iB]_{Reacted}=x, [iB]_{final}=3.0-x, [B]_{final}=1.0+x$ $K=[iB]/[B]$ $2.5=(3-x)/(1+x)$ $x=0.143\ M$ $[iB]_{final}=2.86\ M, [B]_{final}=1.14\ M$ b) The equilibrium will shift to the left, $[B]_{Reacted}=x, [iB]_{final}=2.5+x, [B]_{final}=1.5-x$ $K=[iB]/[B]$ $2.5=(2.5+x)/(1.5-x)$ $x=0.357\ M$ $[iB]_{final}=2.86\ M, [B]_{final}=1.14\ M$