Answer
See the answer below.
Work Step by Step
a) The equilibrium will shift to the right, $[iB]_{Reacted}=x, [iB]_{final}=3.0-x, [B]_{final}=1.0+x$
$K=[iB]/[B]$
$2.5=(3-x)/(1+x)$
$x=0.143\ M$
$[iB]_{final}=2.86\ M, [B]_{final}=1.14\ M$
b) The equilibrium will shift to the left, $[B]_{Reacted}=x, [iB]_{final}=2.5+x, [B]_{final}=1.5-x$
$K=[iB]/[B]$
$2.5=(2.5+x)/(1.5-x)$
$x=0.357\ M$
$[iB]_{final}=2.86\ M, [B]_{final}=1.14\ M$
