Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 15 Principles of Chemical Reactivity: Equilibria - 15-6 Disturbing a Chemical Equilibrium - Applying Chemical Principles - Questions - Page 582: 2

Answer

0.0024 M

Work Step by Step

The concentration of dimer dissociated is x, the concentration of monomer formed is 2x. $K=(2x)^2/(0.015-x)=4.1\times10^{-4}$ $4x^2+4.1\times10^{-4}x-6.15\times10^{-6}=0$ $x=0.00119\ M$ At equilibrium there will be 0.0024 M of monomer.
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