Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - Study Questions - Page 553h: 75

Answer

$4.77\ min$

Work Step by Step

The first rate-constant is $k_1=1/(3\ min)=0.333\ min^{-1}$ From the Arrhenius equation: $\ln(k_2/k_1)=-E_a/R(1/T_2-1/T_1)$ $\ln(k_2/0.333\ min^{-1})=-52000/8.314(1/363-1/373)$ $k_2=0.21\ min^{-1}$ $t_2=1/k_2=4.77\ min$
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