Answer
See the answer below.
Work Step by Step
a,b) At constant [NO2], doubling [F2] doubles the rate, so the reaction is of first-order with respect to F2.
At constant [F2], doubling [NO2] doubles the rate, so the reaction is of first-order with respect to NO2.
$r=k[F_2][NO_2]$
c) For the first line:
$2.0\dot{}10^{-4}\ M/s=k\dot{}0.001\ M\dot{}0.005\ M$
$k=40\ L/mol.s$
