## Chemistry and Chemical Reactivity (9th Edition)

For first-order processes: $ln\left( \dfrac{[N_2O_5]_t}{[N_2O_5]_0}\right)=-kt$ $t_{1/2}=\dfrac{0.693}{k}$ For 99% decomposition: $ln(0.01)=-0.693\times\frac{t}{t_{1/2}}$ $\frac{t}{t_{1/2}}=6.65$