Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 12 The Solid State - 12-4 Bonding in Metals and Semiconductors - Review & Check for Section 12-4 - Page 456: 1

Answer

A

Work Step by Step

Per atom: $68000\ J/mol\div 6.022\times10^{23}\ atom/mol=1.13\times10^{-19}\ J/atom$ $E=h.\nu=h.c/\lambda$ $1.13\times10^{-19}\ J=6.626\times 10^{-34}\ J.s\times 2.998\times 10^8\ m/s\div \lambda$ $\lambda=1.76\times10^{-6}\ m=1760\ nm$
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