## Chemistry and Chemical Reactivity (9th Edition)

A) $C_3H_8(g)+5\ O_2(g)\rightarrow 3\ CO_2(g)+4\ H_2O(l)$ B) Number of moles: $n=0.1\ atm×1.50\ L/((0.082)(293\ K))=0.00624\ mol$ C) From Dalton's law: $0.1\ atm/(0.10 +5.00\ atm)×100\%=1.96\%$ D) Number of moles of excess oxygen: $n=(5.0-5×0.1)\ atm×1.50\ L/((0.082)(293\ K))$ $n=0.281\ mol$ E) $P=3×0.00624\ mol×0.082×316.2\ K/1.50\ L$ $P=0.324\ atm$ F) $P=0.281\ mol×0.082×316.2\ K/1.50\ L$ $P=4.86\ atm$