## Chemistry and Chemical Reactivity (9th Edition)

The number of moles of $CO_2$ is given by: $n=PV/RT$ $n=(44.8/760×1\ atm)×1.50\ L/((0.082)(298\ K))$ $n=0.00362\ mol$ This is also the number of moles of CO. Thus: $0.00362\ mol×28.01\ g/mol=0.101\ g$ Mass of iron: $0.142-0.101=0.041\ g$ Number of moles of iron: $0.041\ g/55.845\ g/mol=0.000729\ mol$ Ratio: $0.00362/0.000729=4.96\approx 5$ Empirical formula: $Fe(CO)_5$