Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403e: 73


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Work Step by Step

Number of moles of CO: $n=(732/760×1\ atm)×5.50\ L/0.082/296\ K$ $n=0.218\ mol$ Number of moles of iron: $3.52\ g\div 55.845\ g/mol=0.063\ mol$ Since the ratio of the two is smaller than the stoichiometric coefficient, iron is in excess. Theoretical yield: $0.218\ mol×1/5×195.90\ g/mol=8.54\ g$
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