Answer
See the answer below.
Work Step by Step
Number of moles of CO:
$n=(732/760×1\ atm)×5.50\ L/0.082/296\ K$
$n=0.218\ mol$
Number of moles of iron:
$3.52\ g\div 55.845\ g/mol=0.063\ mol$
Since the ratio of the two is smaller than the stoichiometric coefficient, iron is in excess.
Theoretical yield:
$0.218\ mol×1/5×195.90\ g/mol=8.54\ g$
