Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403e: 65


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Work Step by Step

From stoichiometry, number of moles of oxygen: 2.0 $PV=nRT$ $V=2.0\ mol×0.082057\ atm.L/mol.K×273\ K/1\ atm$ $V=44.8\ L$
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