Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403c: 43

Answer

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Work Step by Step

From Graham's Law: $\sqrt{\dfrac{\bar{u_A^2}}{\bar{u_B^2}}}=\sqrt{\dfrac{M_B}{M_A}}$ $\sqrt{x^2/(4.28×10^4\ cm/s)^2}=\sqrt{32.0\ g/mol/44.0\ g/mol}$ $x=3.65×10^4\ cm/s$
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