## Chemistry and Chemical Reactivity (9th Edition)

Number of moles of nitrogen, from ideal gas law: $P.V=n.R.T$ $n=1.3\ atm×75.0\ L/0.082057\ L.atm/mol.K/(25+273)\ K$ $n=3.99\ mol$ From stoichiometry: $2.66\ mol$ of $NaN_3$ Mass of sodium azide: $2.66\ mol×65.01\ g/mol=173\ g$