## Chemistry and Chemical Reactivity (9th Edition)

$V_{1}$ = 500 L $P_{1}$ = 67.5 mm Hg $V_{2}$ = 125 mL According to Boyle's law, $P_{1}V_{1} = P_{2}V_{2}$ Or $P_{2}$ = $\frac{P_{1}V_{1}}{V_{2}}$ = $\frac{67.5 mm Hg\times500. mL}{125 mL}$ = 270. mm Hg