Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403a: 5


270. mm Hg

Work Step by Step

$V_{1}$ = 500 L $P_{1}$ = 67.5 mm Hg $V_{2}$ = 125 mL According to Boyle's law, $P_{1}V_{1} = P_{2}V_{2}$ Or $P_{2}$ = $\frac{P_{1}V_{1}}{V_{2}}$ = $\frac{67.5 mm Hg\times500. mL}{125 mL}$ = 270. mm Hg
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