Answer
0.1 L
Work Step by Step
Let $P_{1}$ = 0.80 atm , $V_{1}$ = 0.25 L, $P_{2}$ = 2 atm & $V_{2}$ = ?
Using gas Law Equation $P_{1}V_{1}=P_{2}V_{2}$, we have:
0.80 atm x 0.25 L = 2 atm x $V_{2}$
$V_{2}$ = 0.80 atm / 2 atm x 0.25 L
= 0.1 L