Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 8 - Section 8.2 - Pressure and Volume (Boyle's Law) - Questions and Problems - Page 263: 8.17b

Answer

25 L

Work Step by Step

Let $P_{1}$ = 760 mmHg = 1 atm, $V_{1}$ = 50L, $P_{2}$ = 2 atm & $V_{2}$ = ? Using gas Law Equation $P_{1}V_{1}=P_{2}V_{2}$, we have: 1 atm x 50L = 2 atm x $V_{2}$ $V_{2}$ = 1 atm / 2 atm x 50L = 25 L
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