Answer
328 mmHg
Work Step by Step
$V_{1}$ = 10.0 L
$p_{1}$ = 655 mmHg
$V_{2}$ = 20.0 L
According to Boyle's law, $p_{1}V_{1} = p_{2}V_{2}$
Or $p_{2}$ = $\frac{p_{1}V_{1}}{V_{2}}$ = $\frac{655 mmHg\times10.0 L}{20.0 L}$ = 328 mmHg.
Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)
by Timberlake, Karen C.
Published by
Prentice Hall
ISBN 10:
0321908449
ISBN 13:
978-0-32190-844-5
Chapter 8 - Section 8.2 - Pressure and Volume (Boyle's Law) - Questions and Problems - Page 263: 8.15a
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