Answer
$K_{sp}=2.3^{-9}$
Work Step by Step
1. Find pOH
$pOH= 14-9.68$
$pOH=4.32$
2. Find Concentration of [OH]
$[OH]=10^{-pOH}$
$[OH]=10^{-4.32}$
$[OH]=4.8^{-5}M$
3. Find Ksp
$K_{sp}=[M][OH]$
$K_{sp}=4.8^{-5}\times4.8^{-5}$
$K_{sp}=2.3^{-9}$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 16 - Acid-Base Equilibria and Solubility Equilibria - Questions & Problems - Page 767: 16.60
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