Answer
$x=2.2\times10^{-4}mol/L$
Work Step by Step
1. Write Balanced Equilibrium Equation
$CaF_{2}⇄Ca^{2+}+2F^{-}$
2. Write Ksp equation
$K_{sp}=(x)(2x)^2$
$4.0\times10^{-11}=x(2x)^2$
$x=2.2\times10^{-4}mol/L$
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