Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 4 - The Structure of Atoms - Exercises - The Wave-Particle View of Matter - Page 168: 78

Answer

$1.88\times10^{3}\, m/s$

Work Step by Step

$\lambda=\frac{h}{mv}$ where $\lambda $ is the wavelength, $h$ is the Planck's constant, $m$ is the mass and $v$ is the velocity. $\implies v=\frac{h}{m\lambda}=\frac{6.626\times10^{-34}\,J\cdot s}{(6.64477\times10^{-27}\,kg)(0.529\times10^{-10}\,m)}$ $=1.88\times10^{3}\, m/s$
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