Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 4 - The Structure of Atoms - Exercises - Electron Configurations and the Periodic Table - Page 169: 100


a) Z=20, symbol is Ca, name is Calcium b) 4th period. c) Alkaline earth metals. d) 8 e) 12 f) 0

Work Step by Step

From the given data we can write the electronic configuration as; 1s$^{2}$2s$^{2}$2p$^{6}$3s$^{2}$3p$^{6}$4s$^{2}$. Given that the atom is neutral, so number of electrons= atomic number=20. Highest principal quantum number is 4, hence the atom is in 4th period. Since the last electron enters in s orbital and it is completely filled the atom belongs to alkaline earth metals. Number of electrons in each sub-shell is clear from electronic configuration.
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