Chapter 3 - Chemical Equations and Reaction of Stoichiometry - Exercises - Dilution of Solutions - Page 111: 73

The volume of concentrated sulfuric acid $(18.0M)$ required to prepare this solution is equal to 0.167 L.

1. Find the necessary volume: $C_1 * V_1 = C_2 * V_2$ $ 1.50 M* 2.00L= 18.0M * V_2$ $ 3.00 M*L = 18.0M * V_2$ $V_2 = \frac{3.00 M*L}{18.0M}$ $V_2 = 0.167 L$