#### Answer

The volume of concentrated sulfuric acid $(18.0M)$ required to prepare this solution is equal to 0.167 L.

#### Work Step by Step

1. Find the necessary volume:
$C_1 * V_1 = C_2 * V_2$
$ 1.50 M* 2.00L= 18.0M * V_2$
$ 3.00 M*L = 18.0M * V_2$
$V_2 = \frac{3.00 M*L}{18.0M}$
$V_2 = 0.167 L$